Question

A shopkeeper mixes two varieties of rice costing 8 per kg and 12 per kg in the ratio 1:3. If the cost of the second variety drops to 11.50 per kg, in what ratio should he now mix the two so that the cost of the mixture remains unchanged?

(A) 2:3

(B) 1:6 (C) 3:5

(D) 2:5​

Answer 1

Answer:

c - 3.5/*666+/*563*/+66

Answer 2

Answer:

B

Step-by-step explanation:

To fine the average cost of the initial price it would be

$\frac{(8x1)+(12x3)}{4\\}$

which is 11

so we are looking for the answer that makes 11

which is B

as

$\frac{(8x1)+(11.50x6)}{7\\}$

is also 11

hope this helps :)