A shopkeeper purchase a certain number of books for Rs.960. If the cost per book was Rs.8 less, the number of books that could be bought for RS 960 would be 4more . taking the original cost of each book to be RS X write an equation in X and solve it to find the original cost of each book
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Let cost of 1 book purchased is Rs x
So,
The number of books purchased for Rs 960 will be = 960 / x
Now according to question,
If cost of one book is Rs 8 less
Then
The new cost of 1 book will be = Rs ( x - 8 )
And The number of books will be = 960 / ( x - 8 )
Also it is given,
If cost Rs 8 less then 4 books more can be purchased
So we can form the equation as :
- = 4
= 4
= 4
= 4
7680 = 4 ( x² - 8x )
7680 = 4x² - 32x
4x² - 32x - 7680 = 0
Dividing whole equation by 4
x² - 8x - 1920 = 0
x² - 48x + 40x - 1920 = 0
x ( x - 48 ) + 40 ( x - 48 ) = 0
( x + 40 ) ( x - 48 ) = 0
x = - 40 or x = 48
Neglecting -40 as cost of book can not be negative, So cost of book will be Rs 48 each
Hence,
Cost of 1 book will be Rs 48 each.
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