Math, asked by aditya6575, 1 year ago

A shopkeeper sells 60% of oranges and find 15% of remaining eroded and remove them next day he sell 50% of the remaining oranges and remove the rest as they also got rotten find what percent of total oranges got rotten

Answers

Answered by shubhamatulpathak20
2

Answer:


Step-by-step explanation:

Let the oranges were 100 Kg.

Now the shopkeeper sells 60% of oranges, that means 60Kg of oranges sold out. Therefore the unsold quantity of oranges will be 100-60= 40 Kg.

Now 15% of unsold oranges got rotten so

40x15/100= 6 Kg rotten.

The amount of fresh oranges= 40-6= 34 Kg.

Next day he sells 50% of the fresh oranges i.e 34x50%= 17 Kg

That means 17 Kg of oranges is again rotten.

So total quantity of oranges rotten is 6Kg+ 17 Kg= 23Kg.

Percentage of oranges rotten is 23x100/100= 23%

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