Question

A shopkeeper sells a bag at a loss of 5% If he had sold for Rs 260 more, he would have made a profit of 15%. Find the CP of the bag.



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Answer 1

Answer:

case1:Let CP be x

Loss=5%

SP

1

=x−5%ofx

SP

1

=95%ofx=

100

95

x

Case2: CP=x,

P

2

=15%

SP

2

=x+15%ofx=

100

115

x

Difference in SP is given 260

Thus,

SP

2

−SP

1

=260

100

115x−95x

=260

⇒20x=260×100

⇒x=

20

26000

⇒x=1300

Thus purchase price is 1300 Rs.

Answer 2

Answer:

Rs.1300

Step-by-step explanation:

Let the cost price of bag be x

Now we are given that A shopkeeper sells a bag at a loss of 5% .

So, Loss =     5% × x  = 5/100 × x = 0.05x

S.P. = C.P. - Loss = x-0.05 x =0.95x

Now when he earns profit of 15 %

So, Profit =    15% × x =   15/100 × x   = 0.15x

S.P. = C.P. +Profit  = x+0.15 x =1.15 x

Now we are given that  If he had sold it for Rs 260 more , he would have made a profit of 15% .

So,  

1.15 x - 0.95x =260

0.2x = 260

x = 260/0.2

x = 1300

Hence cost price of the bag is Rs. 1300.