A shopkeeper sells a saree at 8% profit and a sweater at 10% discount,thereby getting a sum of Rs.1008.If she had sold the saree at 10% profit and the sweater at 10% profit,she would have got Rs.1028.Find the cost price of the saree and the list price of the sweater.No $hit answers please.
Answers
Answer
Let Cost Price of saree Rs x
Let Cost Price of sweater Rs y
According to the 1
st
condition of question
Selling Price of saree is Rs. x+
100
8x
=
100
108x
........(1)
Selling Price of sweater is Rs. y−
100
10y
=
100
90x
........(2)
Adding (1) and (2), we get
100
108x
+
100
90y
=1008 .........(3)
According to the 2
nd
condition of question.
Selling Price of saree is Rs. x+
100
10x
=
100
110x
Selling Price of Sweater is Rs. y−
100
8y
=
100
92x
⇒
100
110x
+
100
92y
=1028 .....(4)
Solve (3) and (4)
108x+90y=100800 .......(5)
⇒110x+92y=102800 .......(6)
Subtract (6) − (5), we have
2x+2y=2000
⇒x+y=1000 (7)
Substitute (7) in (5), we get
108x+90(1000−x)=100800
⇒108x−90x=100800−90000
⇒18x=10800
⇒x=600
Cost of saree is Rs 600