Question

a shopkeeper sells a table at 8% profit and a chair at 10% discount ,thereby getting rupees1008.If he had sold the table at 10% profit and chair at 8% diccont ,he would have got rupees 20 more.Find the cost price of the table and the list price of the chair.

Answer 1

Table is sold at a profit of 10%
 
SP of table = x + 10x/00 = 11x/10
 
Chair is sold at a discount of 8%
 
⇒ SP of chair = y - 8y/100 = 92y/100
 
Given that table and chair are sold for Rs 1028
 
11x/10 + 92y/100 = 1028
 
⇒ 110x + 92y/100 = 1028
 
⇒ 110x + 92y = 102800
 
Substituting the value of (i)
 
110 [(5600 - 5y)/6] + 92y = 102800
 
⇒ (616000 - 550y)/6 + 92y = 102800
 
⇒ (616000 - 550y + 552y)/6 = 102800
 
⇒ (616000 + 2y)/6 = 102800
 
⇒ 616000 + 2y = 616800
 
⇒ 2y = 800
 
⇒ y = Rs 400
 
From (i),
 
x = (5600 – 5 × 400)/6
 
x = (5600 - 2000)/6
 
x = 3600/6
 
⇒ x = Rs 600
 
Therefore, CP table = Rs 600
 
Marked price of chair = Rs 400

Answer 2

Answer:

Step-by-step explanation:

Table is sold at a profit of 10%

 

SP of table = x + 10x/00 = 11x/10

 

Chair is sold at a discount of 8%

 

⇒ SP of chair = y - 8y/100 = 92y/100

 

Given that table and chair are sold for Rs 1028

 

11x/10 + 92y/100 = 1028

 

⇒ 110x + 92y/100 = 1028

 

⇒ 110x + 92y = 102800

 

Substituting the value of (i)

 

110 [(5600 - 5y)/6] + 92y = 102800

 

⇒ (616000 - 550y)/6 + 92y = 102800

 

⇒ (616000 - 550y + 552y)/6 = 102800

 

⇒ (616000 + 2y)/6 = 102800

 

⇒ 616000 + 2y = 616800

 

⇒ 2y = 800

 

⇒ y = Rs 400

 

From (i),

 

x = (5600 – 5 × 400)/6

 

x = (5600 - 2000)/6

 

x = 3600/6

 

⇒ x = Rs 600

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