Question

A shopkeeper sells a table at 8% profit and a chair at 10% discount, thereby getting
1008. If he had sold the table at 10% profit and chair at 8% discount, he would have
320 more. Find the cost price of the table and the list price of the chair.​

Answer 1

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Given :

☞ Profit on Table = 8 %

☞ Discount on chair = 10 %

According to the question :

☞ Let Cost price of table be ' Rs. a '

☞ Let Cost price of chair be ' Rs. b '.

Equation :

☞ [ a × ( 100 + 8 ) / 100 ] + [ b × ( 100 - 10 ) / 100 ] = 1008

=> ( 100a + 8a / 100 ) + ( 100b - 10b / 100 ) = 1008

=> 108a + 90b = 1008 × 100

=> 108a + 90b = 100800

=> 6a + 5b = 5600 ......... ( 1 )

And :

☞ [ a × ( 100 + 10 ) / 100 ] + [ b × ( 100 - 8 ) / 100 ] = 1008 + 20

=> 110a + 100 + 92b / 100 = 1028

=> 110a + 92b = 102800

=> 55a + 46b = 51400 ......... ( 2 )

Multiplying ( 1 ) by 55 and ( 2 ) by

6 , we get :

=> 330a + 275b = 30800 ......... ( 3 )

=> 330a + 276b = 308400 ......... ( 4 )

Subtracting Equation ( 4 ) from

( 3 ) we get :

=> - b = - 400

=> b = 400.

Substituting the value of ' b ' in equation ( 1 ) :

=> 6a + 5 ( 400 ) = 5600

=> 6a + 2000 = 5600

=> 6a = 5600 - 2000

=> 6a = 3600

=> a = 3600 / 6

=> a = 600.

Finally :

Cost price of the table = Rs. 600.

List price of chair = b × ( 100 - 80 ) %

=> b × 90 %

=> 400 × 90 / 100

=> Rs. 360.

$<marquee><b><font colour="red">$ Therefore, The cost price of table = Rs. 600 and List price of chair = Rs. 360.

Answer 2

Step-by-step explanation:

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