A shopkeeper sells a table at 8%profit and a chair at 10% discount thereby getting 1008. If he had sold the table at 10% profit and chair at 8% discount he would have got 20 more. Find the cost price of the table and list price of the chair.
Answers
Answer:
Given,
Profit on table =8%
Discount on chair =10%
Let
C.P. of table = Rs x and
C.P. of chair = Rs y
Then according to the question,
100
x×(100+8)
+
100
y×(100−10)
=1008
⇒108x+90y=100800
⇒6x+5y=5600 … (i)
And,
100
x×(100+10)
+
100
y×(100−8)
=1008+20
⇒110x+92y=102800
⇒55x+46y=51400 … (ii)
Now, multiplying (i) by 55 and (ii) by 6, we have
330x+275y=308000 ... (iii)
330x+276y=308400 ... (iv)
Subtracting equation (iv) from (iii), we get
−y=−400
⇒y=400
On substituting the value of y in equation (i), we get
6x+5(400)=5600
⇒6x=5600−2000
⇒x=
6
3600
⇒x=600
Hence,
Cost Price of the table = Rs 600
List price of chair =400×
100
90
= Rs 360
Answer:
Profit on table =8%
Discount on chair =10%
Let
C.P. of table = Rs x and
C.P. of chair = Rs y
Then according to the question,
100
x×(100+8)
+
100
y×(100−10)
=1008
⇒108x+90y=100800
⇒6x+5y=5600 … (i)
And,
100
x×(100+10)
+
100
y×(100−8)
=1008+20
⇒110x+92y=102800
⇒55x+46y=51400 … (ii)
Now, multiplying (i) by 55 and (ii) by 6, we have
330x+275y=308000 ... (iii)
330x+276y=308400 ... (iv)
Subtracting equation (iv) from (iii), we get
−y=−400
⇒y=400
On substituting the value of y in equation (i), we get
6x+5(400)=5600
⇒6x=5600−2000
⇒x=
6
3600
⇒x=600
Hence,
Cost Price of the table = Rs 600
List price of chair =400×
100
90
= Rs 360
Answered By Aashish