A shopkeeper sells a table at a profit of 8% and a chair at a discount of 10%, there
by getting a sum of 7200. If he had sold the table at a profit of 10% and the chair at
a discount of 8%, he would have received 7340. Find the cost price of the table
and the list price of the chair.
Answers
Answer:
Table is sold at a profit of 10%
SP of table = x + 10x/00 = 11x/10
Chair is sold at a discount of 8%
⇒ SP of chair = y - 8y/100 = 92y/100
Given that table and chair are sold for Rs 1028
11x/10 + 92y/100 = 1028
⇒ 110x + 92y/100 = 1028
⇒ 110x + 92y = 102800
Substituting the value of (i)
110 [(5600 - 5y)/6] + 92y = 102800
⇒ (616000 - 550y)/6 + 92y = 102800
⇒ (616000 - 550y + 552y)/6 = 102800
⇒ (616000 + 2y)/6 = 102800
⇒ 616000 + 2y = 616800
⇒ 2y = 800
⇒ y = Rs 400
From (i),
x = (5600 – 5 × 400)/6
x = (5600 - 2000)/6
x = 3600/6
⇒ x = Rs 600
Answer:
CP table = Rs 600
Marked price of chair = Rs 400
Step-by-step explanation:
Table is sold at a profit of 10%
SP of table = x + 10x/00 = 11x/10
Chair is sold at a discount of 8%
⇒ SP of chair = y - 8y/100 = 92y/100
Given that table and chair are sold for Rs 1028
11x/10 + 92y/100 = 1028
⇒ 110x + 92y/100 = 1028
⇒ 110x + 92y = 102800
Substituting the value of (i)
110 [(5600 - 5y)/6] + 92y = 102800
⇒ (616000 - 550y)/6 + 92y = 102800
⇒ (616000 - 550y + 552y)/6 = 102800
⇒ (616000 + 2y)/6 = 102800
⇒ 616000 + 2y = 616800
⇒ 2y = 800
⇒ y = Rs 400
From (i),
x = (5600 – 5 × 400)/6
x = (5600 - 2000)/6
x = 3600/6
⇒ x = Rs 600
Therefore, CP table = Rs 600
Marked price of chair = Rs 400