Question

A shopkeeper sells an article for Rs. 2400 for loss of 4%.Find the CP. Also find the SP at which he should have sold in order to get 8% profit.​

Answer 1

Given

• Seliing price (SP)=Rs.2400
• Loss%= 4%

To Find

• Cost price (CP)
• the SP at which he should have sold in order to get 8% profit.

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Formula Used

• $\boxed{ \pink{\sf CP= \left(\dfrac{SP×100}{100-Loss \%} \right)}}$
• $\boxed{\pink{\sf SP= \left( \dfrac{100+P \%}{100} \right) × CP}}$

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Solution

Here's

SP= Rs.2400

Loss=4%

On putting the value of SP and Loss In Formula We get,

$\\{\implies\sf CP= \left(\dfrac{2400×100}{100-4} \right)}$

${\implies\sf CP= \dfrac{240000}{96} }$

${~~~~~~~~~\sf CP= 2500}$

Now

We Need To Find

• SP at which he should have sold in order to get 8% profit.

CP= Rs.2500

Profit = 8%

On Subtuting The value of CP and Profit In Formula we get,

$\\{\implies\sf SP= \left( \dfrac{100+8}{100} \right) × 2500}$

${\implies\sf SP= \ \dfrac{108}{100} × 2500}$

${\implies\sf SP= 108 × 25}$

$~~~~~~~~~~\sf SP= 2700$

• Cost price=Rs.2500
• Selling Price at which he should have sold in order to get 8% Profit =Rs.2700

More Useful Formula

$\boxed{\begin{minipage}{5cm}\bigstar \:\underline{\textbf{Profit and Loss Formulas :}}\\\\ \\ \sf {\textcircled{\footnotesize\textsf{1}}} \:S.P. = \sf \bigg\lgroup\dfrac{100 + Profit \%}{100}\bigg\rgroup \times CP \\\\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:C.P. = \sf \dfrac{S.P. \times 100}{100 + Profit \%} \\\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Profit = \sf \dfrac{Profit \% \times C.P.}{100} \\\\\\ \sf{\textcircled{\footnotesize\textsf{4}}} \: \:Profit (gain) = S.P. - C.P. \\\\\\\sf{\textcircled{\footnotesize\textsf{5}}} \: \: \sf Profit \% = \dfrac{Profit}{C.P.} \times 100 \end{minipage}}$

Answer 2

Step-by-step explanation:

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