A shopkeeper sells an article for Rs. 60 at a profit of 20%. At what price should he sell it to gain 30%?
option:
a) rs:53
b)rs:68
c)rs:70
d)rs:65
Answers
s.p of article=rs60
gain - 20%
cp = sp x 100 = 60 x 100 = 6000 = rs50 =cp
gain + 100 20+100 120
C.P= RS 50
gain 30% = 50 x 30 = 15 gain
100
sp = cp + gain=50+15=65 rupees ANS
Answer:
Cost of painting = ₹ 7,12,425 .
\bold{\underline{\underline{Step\:-\:by\:-\:step\:explanation:}}}
Step−by−stepexplanation:
Given :
Length of the black board is 17 dm 7 cm
Breadth of the black board is 11 dm 5 cm
Cost of painting the blackboard is 35 paise per square centimeter.
To find :
Cost of painting the blackboard.
Solution :
Since the values are given in decimetre, we will first convert the units.
For length :-
1 dm = 10 cm
•°• 17 dm = 17(10) = 170 cm
Length of the blackboard = 170 + 7
•°• Length (l) = 177 cm
For breadth :-
\rightarrow→ \bold{Breadth=11(10)}Breadth=11(10)
\rightarrow→ \bold{Breadth=110}Breadth=110
•°• Breadth(b) = 110 + 5 = 115 cm
So now we have the length and breadth of the black board in same unit. So let's find the area of the blackboard.
Area of blackboard :-
\rightarrow→ \bold{Area\:=\:length\times\:breadth}Area=length×breadth
Block in the values,
\rightarrow→ \bold{Area\:=\:177\times\:115}Area=177×115
\rightarrow→ \bold{Area\:=20355}Area=20355
•°• Area = 20355 cm²
Now, to find the cost.
Cost required will be area of the blackboard times cost of painting the blackboard per square centimeter.
Cost of painting,
\bold{Area\:of\:blackboard\times\:rate\:per\:square\:centimeter}Areaofblackboard×ratepersquarecentimeter
\rightarrow→ \bold{20355\times\:35}20355×35
\rightarrow→ \bold{712425}712425
•°• Cost of painting the blackboard at the rate of 35 paise per square centimeter is ₹ 7, 12, 425.