Question

A shopkeeper sells an article for Rs. 60 at a profit of 20%. At what price should he sell it to gain 30%?

option:
a) rs:53
b)rs:68
c)rs:70
d)rs:65

Answer 1

s.p of article=rs60

gain - 20%

cp =  sp x 100     =     60 x 100  =   6000  = rs50 =cp  

         gain + 100        20+100         120

C.P= RS 50

gain 30% = 50 x 30    =   15 gain

                           100

sp = cp + gain=50+15=65 rupees ANS

Answer 2

Answer:

Cost of painting = ₹ 7,12,425 .

\bold{\underline{\underline{Step\:-\:by\:-\:step\:explanation:}}}

Step−by−stepexplanation:

Given :

Length of the black board is 17 dm 7 cm

Breadth of the black board is 11 dm 5 cm

Cost of painting the blackboard is 35 paise per square centimeter.

To find :

Cost of painting the blackboard.

Solution :

Since the values are given in decimetre, we will first convert the units.

For length :-

1 dm = 10 cm

•°• 17 dm = 17(10) = 170 cm

Length of the blackboard = 170 + 7

•°• Length (l) = 177 cm

For breadth :-

\rightarrow→ \bold{Breadth=11(10)}Breadth=11(10)

\rightarrow→ \bold{Breadth=110}Breadth=110

•°• Breadth(b) = 110 + 5 = 115 cm

So now we have the length and breadth of the black board in same unit. So let's find the area of the blackboard.

Area of blackboard :-

\rightarrow→ \bold{Area\:=\:length\times\:breadth}Area=length×breadth

Block in the values,

\rightarrow→ \bold{Area\:=\:177\times\:115}Area=177×115

\rightarrow→ \bold{Area\:=20355}Area=20355

•°• Area = 20355 cm²

Now, to find the cost.

Cost required will be area of the blackboard times cost of painting the blackboard per square centimeter.

Cost of painting,

\bold{Area\:of\:blackboard\times\:rate\:per\:square\:centimeter}Areaofblackboard×ratepersquarecentimeter

\rightarrow→ \bold{20355\times\:35}20355×35

\rightarrow→ \bold{712425}712425

•°• Cost of painting the blackboard at the rate of 35 paise per square centimeter is ₹ 7, 12, 425.