A shopkeeper sells four varieties of perfumes and he has a large number of bottles of the same size of each variety in his stock. There are 6 places in row in his showcase. The number of different ways of displaying the four varieties of perfumes in the showcase is:
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Answer:
There are 5 places
So three items in 5 places
So total nos of arrangement including repetition and not including all items is 3
5
=243
Total arrangement where only two items in 5 places = (
2
3
)2
5
−3
Total arrangement where 3 items in 5 places =243−((
2
3
)2
5
−3)
Total arrangement where 3 items in 5 places =243−3×32+3=150
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