Question

A shopkeeper sells one transistor for Rs.840 at a and a gain of 20 percent and another for Rs. 960 at a loss of 4 percent. His total gain or less percent is ​

Answer 1

Answer:

${\huge{\underline{\underline{\bold{\red{Answer:-}}}}}}$

${\huge{\underline{\small{\bold{\blue{case\:1)}}}}}}$

S.P of transistor = Rs 840

${\huge{\underline{\small{\bold{\red{profit:-}}}}}}$

20%

${\huge{\underline{\small{\bold{\pink{by\:unitary\:method\:C.P :-}}}}}}$

(100/120) × 840= 700Rs

${\huge{\underline{\small{\bold{\green{case\:2)}}}}}}$

S.P of transistor = Rs960

${\huge{\underline{\small{\bold{\red{loss:-}}}}}}$

4%

${\huge{\underline{\small{\bold{\pink{by\:unitary\:method\:C.P :-}}}}}}$

(100/96) × 960 = 1000 Rs

${\huge{\underline{\small{\bold{\blue{total\:C.P :-}}}}}}$

700 + 1000 =1700 Rs

${\huge{\underline{\small{\bold{\purple{total\:S.P :-}}}}}}$

840 + 960 = 1800 Rs

There is a profit of = 1800 - 1700 = Rs100

${\huge{\underline{\bold{\blue{therefore,}}}}}$

profit% = (100/1700) × 100 = 100/17 = 5.882%

${\huge{\underline{\small{\bold{\blue{final\: Answer :-}}}}}}$

5.882%

Answer 2

Answer:

Answer : Total gain % is 5.9%

Step-by-step explanation:

Case 1 :

The Selling Price of the Transistor = RS 840

The gain percent = 20%

The Cost Price of the Transistor = SP × 100 / 100+gain%

CP = RS 840 × 100 / 100 + 20

CP = 840 × 100 / 120

.°. CP of the Transistor = RS 700

Case 2 :

The Selling Price of the Transistor = RS 960

The loss percent = 4%

The Cost Price of the Transistor = SP × 100 / 100+loss%

CP = RS 960 × 100 / 100 - 4

CP = RS 960 × 100 / 96

.°. Cost Price of the Transistor = RS 1000

Case 3 :

The Total Cost Price of the Transistor = RS 700 + RS 1000 = RS 1700

The Total Selling Price of the Transistor = RS 840 + RS 960 = RS 1800

.°. Profit = Total Selling Price - Total Cost Price = RS 1800 - RS 1700 = RS 100 ( i.e the Selling Price is greater than Cost Price then it becomes Profit )

Profit % = Profit ×100 / Total Cost Price = 100 × 100/ 1700 = RS 100 / 17 = 5.9% ( approximately )