Question

a shopkeeper sells one transistor for rs 840 at a profit of 20percent and another at 960 rs at a loss of 4 percent .his total profit or loss per cent is​

Answer 1

C.P. of 1st transistor = Rs. 100

------- × 840 = rs. 700

120

C.P. of 2nd transistor = Rs. 100

--------- × 960 = rs.100

96

so, total c.p. = Rs. (700+100) = rs. 1700

total s.p. = Rs. ( 840 + 960) = rs. 1800

therefore, Gain% = 100 15

--------- × 100 % = 5 ----- %

1700 17

hope it help u

Answer 2

⇒ Given :-

• A shopkeeper,

• sells one transistor for Rs. 840,

• at a profit of 20%,

• another at 960 rs at a loss of 4%.

⇒ To Find :-

• his total profit or loss %

⇒ Solution :-

• S.P of the first transistor = Rs. 840

• Profit of the first transistor = 20%

• S.P of the second transistor = Rs. 960

• Loss of the second transistor = 4%

• C.P of first transistor = ( 100 ÷ 100 + 20 ) x 840

                                           = 100 ÷ 120 x 840

                                           = Rs. 700

• C.P of the second transistor = ( 100 ÷ 100 - 4 ) x 960

                                                        = 100 ÷ 96 x 960

 

                                                         = Rs. 1000

• Total S.P of the transistor = Rs. 840 + 960

                                                   = Rs. 1800

• Total C.P of the transistor = Rs. 700 + 1000

                                                   = Rs. 1700

• Profit = Rs. 1800 - 1700 = Rs. 100

• ∴ Profit percent = 100 ÷ 1700 x 100

                                   = 5 $\sf{\underline{\dfrac{15}{17}}$ %

$\huge{\boxed{\sf{\ Hence\:\:Proved}}}$