Question

A shopkeeper sells two quality tea at rate of Rupees33/kg and
Rupees30/kg, gaining 10% and 20% profit respectively. If he
mixes the two variants in the ratio 3:2 and sells the
mixture at Rupees21/kg, what is his gain or loss ? PLEASE ANSWER TO MY QUESTION WITH THE FULL METHOD.​

Answer 1

Answer:

HIS TOTAL LOSS IS ₹34

Step-by-step explanation:

FOR THE FIRST QUALITY OF TEA,

SP = ₹33

PROFIT%=10%

LET THE CP BE x

SO,

P%=(P/CP)*100

10=[(33-x)/x]*100

10/100=[(33-x)/x]

1/10=[(33-x)/x]

x=10(33-x)

x=330-10x

11x=330

x=30

SO,

CP = ₹30

FOR THE SECOND QUALITY OF TEA,

SP=₹30

PROFIT%=20%

LET THE CP BE x

SO,

P%=(P/CP)*100

20=[(30-x)/x]*100

1/5=[(30-x)/x]

x=5(30-x)

x=150-5x

6x=150

x=150/6

x=₹25

SO,

CP = ₹25

NOW,

RATIO=3:2

SO,

LET THE COMMON RATIO BE x

SO,

FIRST TEA QUANTITY=3x

SECOND TEA QUANTITY=2x

SO,

A.T.Q.,

3x+2x=₹21

5x=21

x=21/5

x=₹4.20

SO,

HIS TOTAL SP=₹21

HIS TOTAL CP = ₹30+₹25

                         = ₹55

SO,

HIS TOTAL LOSS = ₹55-₹21

                              = ₹34

I HOPE YOU UNDERSTOOD THE QUESTION!!!