Question

A shopkeeper sells two watches each of rupees 990,one at 10% profit and another at 10% loss,in whole what did shopkeeper get?​

Answer 1

Step-by-step explanation:

10 % profit on first watch

990+99=1089

10% loss on second watch

990-99=891

Total earning =1089+891=1980

Hope this helps you

Answer 2

Given:

A shopkeeper sells two watches each of rupees 990,one at 10% profit and another at 10% loss, in whole what did shopkeeper get?​

Solution:

Assume that the CP of the watch sold at loss is $x$ and the CP of watch sold at the profit is $y$,

According to the question,

Find the value of $x$,

$\[x\left( {1 - \frac{{10}}{{100}}} \right) = 990\]$

$\[ \Rightarrow x \times \frac{{90}}{{100}} = 990\]$

$\[ \Rightarrow x = 11 \times 100\]$

$\[ \Rightarrow x = 1100\]$

Find the value of $y$,

$\[y\left( {1 + \frac{{10}}{{100}}} \right) = 990\]$

$\[ \Rightarrow y \times \frac{{11}}{{10}} = 990\]$

$\[\begin{array}{l} \Rightarrow y = 90 \times 10\\ \Rightarrow y = 900\end{array}\]$

Total CP,

$\[\begin{array}{l} = 1100 + 900\\ = 2000\end{array}\]$

Total SP,

$\[\begin{array}{l} = 990 + 990\\ = 1980\end{array}\]$

Calculate his total loss,

$\[\begin{array}{l} = 2000 - 1980\\ = Rs.20\end{array}\]$

Evaluate the percentage loss,

$\[\begin{array}{l} = \frac{{20}}{{2000}} \times 100\\ = 1\% \end{array}\]$

Hence, shopkeeper get a loss of 1%.