*A shopkeeper sold 11/15 of the total number of oranges which he had in his shop and now he is left with 124 oranges. Find the number of oranges he had sold.* if you don't know the answer don't answer,(don't spam you will be reported)
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Answer:
Let the number toys be xy. which can be written as 10x+y.
where, y is the digit of units place and x is the digit of tens place.
And price of each toy =ab which can be written as 10a+b.
where, b is the digit of units place and a is the digit of tens place.
Now,
A/q , the shopkeeper has 81 items more than actual.
10x+y=10y+x+81
or, 9x−9y=81
or, x−y=9
The only possible solution of above equation is x=9 and y=0.
So, actual number of toys sold =90
The wrongly recorded number of toys sold =9
∴ Wrongly recorded selling price of a toy =
9
Rs.882
=Rs.98
So, the correct selling price of a toy =Rs.89
Hence, A is the correct answer.
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