Math, asked by koushikm34, 1 month ago

A shopkeeper sold 3 pencils and 4 pens to a customer for Rs.44.A little later another customer purchased 6 pencils and 8 pens for Rs.90.Form a pair of linear equations to represent this situation.​

Answers

Answered by amitnrw
1

Given : A shopkeeper sold 3 pencils and 4 pens to a customer for Rs.44.

A little later another customer purchased 6 pencils and 8 pens for Rs.90.

To Find   : Form a pair of linear equations to represent this situation.​

Solution:

Let say pencil cost = Rs x

and Pen cost = Rs y

shopkeeper sold 3 pencils and 4 pens to a customer for Rs.44.

=> 3x  + 4y  = 44

6 pencils and 8 pens for Rs.90.

=> 6x  + 8y  = 90

a pair of linear equations to represent this situation.​

3x  + 4y  = 44

6x  + 8y  = 90

additional info : no solution exist for this linear pair of equation  so can be mistake in data in Question

as  6x  + 8y  = 90 => 3x + 4y = 45  

while another equation is 3x + 4y = 44  

Hence no solution

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Answered by RvChaudharY50
2

Given :-

  • A shopkeeper sold 3 pencils and 4 pens to a customer for Rs.44.
  • A little later another customer purchased 6 pencils and 8 pens for Rs.90.

Solution :-

Let us assume that , SP of 1 pencil is Rs.x and SP of 1 pen is Rs.y .

so,

→ SP of 3 pencil + 4 pens = Rs.44

→ 3 * x + 4 * y = 44

→ 3x + 4y = 44 ---------- Equation (1)

similarly,

→ SP of 6 pencil + 8 pens = Rs.90

→ 6 * x + 8 * y = 44

→ 6x + 8y = 90 ---------- Equation (2)

now, Equation (2) can be written as,

→ 2(3x + 4y) = 90

→ 3x + 4y = 45

but first Equation also says that,

→ 3x + 4y = 40

therefore,

→ 3x + 4y = 40

→ 3x + 4y = 45

→ 40 ≠ 45 .

which is not possible .

But we can represent both equations a pair of linear equations as ,

→ 3x + 4y = 44 .

→ 6x + 8y = 90 .

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