Math, asked by danis9008, 1 month ago

A shopkeeper sold 3by7 of 8 kg 750 g of his vegetables in the morning and sold 7by10 of the remaining vegetables in the evening.
How much more of the vegetables in grams did he sell in the morning than in the evening?

Answers

Answered by ziafirdous91
7

Answer:

solution:

Total quantity of vegetables are = 8 kg 750 g

= 8×1000 +750g

= 8000+750 g

= 8750g

Shopkeeper sells in the morning=3/7 of 8750g

= 3/7×8750 g

. =3750 g

Shopkeeper sells in evening

= 7/10 ×( 8750-3750)

= 7/10 × 5000

= 3500 g

The vegetables he sells more in the morning than in the evening is = 3750 - 3500 g

= 250g ans.

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