A shopkeeper sold a saree and a sweater together for ₹1050, thereby making a profit of 10% on a saree and 25% on a sweater. If he had taken a profit of 25% on the saree and 10% on the sweater, he would have got ₹15 more. Find the cost price of each.
Answers
Question:-
A shopkeeper sold a saree and a sweater together for ₹1050, thereby making a profit of 10% on a saree and 25% on a sweater. If he had taken a profit of 25% on the saree and 10% on the sweater, he would have got ₹15 more. Find the cost price of each.
To Find:-
The cost price of Saree ans sweater.
Solution:-
Let the cost price of the saree be ₹x and the cost price of the sweater be ₹y.
- Profit on saree = 10%
- Profit of sweater = 25%
As the selling price of both is ₹1050,
Now,profit on saree = 25%,
- Profit on sweater = 10%
New S.P. of saree and sweater together =
₹1050 + ₹15 = ₹1065,
On adding (i) and (ii),we get.
47x + 47y = 42300 => x+y = 900 ...(iii)
Subtracting (i) and (ii),we get
3x – 3y = 300 => x–y = 100 ...(iv)
Adding (iii) and (iv),we get
2x = 1000 => x = 500.
Substituting this value of x in (iii),we get
500 + y = 900 => y = 400.
Hence,the cost price of the saree is ₹500 and the cost price of the sweater is ₹400.
Answer:-
- Cost Price of the saree is = ₹500 and
- cost price of the sweater is = ₹400.
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