Question

a shopkeeper sold an article offering at a discount of 5% and earned a profit of 23.5%. what would have been the percentage of profit earned if no discount was offered ?

Answer 1

HELLO FRIEND HERE IS YOUR ANSWER,,,,,,

Let us set a value for the cost price , that is , Rs. 100.

Therefore, the selling price will be

= > $100 + 23.50$

= > $Rs. 123.50$

Now, let Marked price be set as a variable of Rs. "x".

Therefore,,,

$\frac{95}{100}x = 123.50$

$95x = 123.50 \times 100$

Now,

$x = \frac{12350}{95} \\ \\ \\ = Rs. 130$

$\therefore \: \: Selling \: Price = Rs. 130 \\ \\ \\ Cost \: Price = Rs. 100$

$\therefore \: \: Profit \: attained = Selling \: Price - Cost \: Price$

$Profit \: attained = 130 - 100 \\ \\ \\ = > Profit \: attained = 30$

$\therefore \: \: Total \: Percentage \: Profit = \frac{Total \: Profit}{Cost \: Price} \times 100%$

Now, By the above formulae we can calculate and find the final answer,,,,

$\therefore \: \: Total \: Percentage \: Profit = \frac{30}{100} \times 100$ %

$Total \: Percentage \: Profit = 30$ %

ANSWER $\boxed{\textbf{\huge{30}}}$ %

HOPE THIS HELPS YOU AND CLEARS YOUR DOUBTS FOR PROFIT AND LOSS CONCEPTUAL QUESTIONS !!!!!

Answer 2

Answer:

30 %.

Step-by-step explanation:

Let the marked price of the article = x,

Since, the discount is 5 %,

So, the selling price of the article = (100-5)% of marked price

= 95 % of x

= 0.95x

Now, the profit % = 23.5 %,

Also,

$\text{ profit}\% = \frac{\text{Selling price - Cost price}}{\text{Cost price}}\times 100$

$23.5 = \frac{0.95x-\text{C.P.}}{C.P.}\times 100$

$0.235\text{ C.P.} = 0.95x-\text{C.P.}$

$1.235\text{ C.P.}=0.95x$

$\implies \text{C.P.}=\frac{0.95x}{1.235}$

When discount is not allowed,

Then S.P. = x,

Hence,

$\text{ profit}\% = \frac{x-\frac{0.95x}{1.235}}{\frac{0.95x}{1.235}}\times 100$

$=\frac{1.235x-0.95x}{0.95x}\times 100$

$=\frac{0.285}{0.95}\times 100=\frac{28500}{95}=30\%$