Math, asked by ram181914, 9 months ago

A shopkeeper sold two articles at the same selling price first at 15% profit on cost price second article 8(16/23]% profit on selling price. if the cost price of the article is 840 then find the cost price of the first article?​

Answers

Answered by aquialaska
1

Answer:

Cost Price of 2nd Article is Rs. 800

Step-by-step explanation:

Given: Cost Price of 2nd Article = Rs. 840

           Profit Percentage on CP of 1st article = 15%

           Profit Percentage on SP of 2nd article = 8/frac{16}{23}=\frac{200}{23} %

           Selling price of both article is same.

To find: Cost Price of 1st Article.

Let Selling Price of 2nd Article = x

According to the question,

x=840+\frac{\frac{200}{23}}{100}\times x

x-\frac{2}{23}\times x=840

\frac{21}{23}x=840

x=920

Now, let cost price of 1st Article = y

y+\frac{15}{100}y=920

\frac{115}{100}y=920

y=800

Therefore, Cost Price of 2nd Article is Rs. 800

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