A shopkeeper sold two electronic gadgets for rs 44000 each. The shopkeeper made a loss of 12% on one and a profit of 10% on the other. Find his overall gain or loss.(hint=find C.P. of each)
Answers
Let us take the vlaue of first electroic gadgets as x
4400/x = 88/100 (Selling price = orginal price 100% - 12% loss)
x = 4400 x 100/88
= 440000/88 = 5000
So the price of first electronic gadgets is Rs. 5000
Let us take the vlaue of second electronic gadget as y
4400/x = 110/100 (Selling price = orginal price 100% and 10% profit)
x = 4400 x 100/110
= 440000/110 = 4000
So the price of second electronic gadget is Rs. 4000
Cost of two electronic gadgets = 4000 + 4000 = 8000
Selling price = 4400 + 4400 =8800
He made profit by 8800 - 8000 = Rs. 800
in % = 800 x 100 /8000 = 10 %
Answer: ₹2,000
Step-by-step explanation:
Let the C.P of one of the gadgets be x.
S.P of the gadget= ₹44,000
Loss=12%
ATQ, x - 44,000 X 100
_______________ = 12
x
=> 88x = 44,00,000
=> x = 44,00,000
________
88
=> x = 50,000
Therefore,C.P= ₹50,000
Let the C.P of the other gadget be y.
S.P of the other gadget = ₹44,000
Profit=10%
ATQ, y + 44,000 X 100
______________ = 10
y
=> 110y = 44,00,000
=> y = 44,00,000
________
110
=> y = 40,000
Therefore, C.P= ₹40,000
Total S.P = ₹( 44,000 + 44,000 )
= ₹ 88,000
Total C.P = ₹( 50,000 + 40,000 )
= ₹ 90,000
Therefore Loss = C.P - S.P
= ₹( 90,000 - 88,000 )
= ₹ 2,000