Math, asked by pratiktheurkar99, 6 hours ago

A shopkeeper sold two sets of radio at rupees 792

Answers

Answered by kushwaneha
0

Answer:

Correct option is

C

loses 1%

Selling price of watch A and watch B= Rs. 425

Let cost price of watch A=x

Profit =10%

100

110

x=425

x=386.36

Let cost price of watch B=y

Loss =10%

100

90

y=425

y=472.22

Net cost price =x+y=858.5858

Net selling price =850

Loss%=

858.58

858.5858−850

×100=1%

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