Question

A shopkeeper sold two tables for rupees 1485 each on one he gains 10% and on other he lost 10% gain or loss in the whole transaction
of math प्लीज ​

Answer 1

Answer:

Profit=1485-1350= ₹135 . let the cost of one table which loss 10% be y. ... So selling price of the table =y-0.1y=0.9y=1485=> y=14850/9= ₹1650.

Answer 2

Let's name the two tables as Table 1 and Table 2.

Table 1:

Selling Price = Rs. 1485

Profit% = 10%

Cost Price = ?

$c.p. = \frac{s.p. \times 100}{100 + p\%}$

$c.p. = \frac{1485 \times 100}{100 + 10}$

$c.p. = \frac{145800}{110}$

C.P. = Rs. 1350

Table 2:

Selling price = Rs. 1485

Loss% = 10%

Cost Price = ?

$c.p. = \frac{s.p. \times 100}{100 - l\%}$

$c.p. = \frac{1485 \times 100}{100 - 10}$

$c.p. = \frac{148500}{90}$

C.P. = Rs. 1650

_____________________________

Total S.P. = 1485×2

= Rs. 2970

Total C.P. = 1350+1650

= Rs. 3000

2970 < 3000

S.P. < C.P.

As C.P is greater than S.P., therefore it is a loss.

Loss = C.P. - S.P.

Loss = 3000-2970

Loss = Rs. 30

Therefore the shopkeeper suffered a loss of Rs. 30.