Question

A shopkeeper sold two tables for rupees 1485 each one of the gains 10% and one of the Other loses 10% his gain or loss percent in whole transaction is

Answer 1

let the cost of one table sold by shopkeeper which gains 10% be x. gain=(10/100)x=0.1x
So since selling price= x+0.1x=1.1x=1485=> x=14850/11=1350. Profit=1485-1350= ₹135 .
let the cost of one table which loss 10% be y. Loss=10/100(y) =0.1y. So selling price of the table =y-0.1y=0.9y=1485=> y=14850/9= ₹1650. Loss=1650- 1485= ₹165 .
Net loss=165-135= ₹30.
Cost of two tables=1650+1350=₹3000.
Loss%=30(100)/3000=1 % .
Hence there is a loss of 1% .
Hope it helps you...