Question

A shopkeeper wants to sell 20 item each at RS. 60 earn some profits. but for every RS 10 increment in selling price of one item, he left with one unsold item. find at what selling price, he would be able to maximize his profit.
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Answer 1

Step-by-step explanation:

x is the each selling price

y is his buying price

20 items sell in 20x rupees

20 items buy in 20y rupees

20x - 20y = 60×20

or, 20(x-y) = 60 ×20

or, x = 60(y+3)

y+10×19 - 20x = 60×19

or, y+190-20x = 114

or,y-20x =-76

or, x = 76-y/20

60(y+3) = 76-y/20

or, 1200(y+3) = 76 - y

or, 1200y + 3600 = 76 - y

or, 1201y =