A shopkeper purchased 60 articles at ₹ 150 each. He sold one-third of them at a loss
of 6%.At what price each must he sell the remaining so as to to gain 10% on the whole deal.
Answers
Answer:-
Given:
Total number of articles = 60
CP of each article = Rs. 150
CP of 60 articles = 150 * 60 = Rs. 9000
1/3 of the articles are sold at Loss of 6%.
1/3 of articles = 1/3 * 60 = 20
⟹ CP of 20 articles = 20 * 150 = Rs. 3000
We know that,
SP = (100 - loss%)/100 * CP
⟹ SP of 20 articles = (100 - 6)/100 * 3000
⟹ SP of 20 articles = 94 * 30
⟹ SP of 20 articles = Rs. 2820
Also given that,
Total gain% = 10%
Gain% = Gain/CP * 100
⟹ 10 = Gain/9000 * 100
⟹ 10 * 9000 * 1/100 = Gain
⟹ Rs. 900 = Gain
We know,
Gain = Total SP - Total CP.
We have:
- Total SP = SP of 20 articles + SP of 40 articles.
- Total CP = CP of 60 articles = 9000.
So,
⟹ 900 = 2820 + SP of 40 articles - 9000
⟹ 900 - 2820 + 9000 = SP of 40 articles
⟹ Rs. 7080 = SP of 40 articles
∴ The remaining articles should be sold for Rs. 7080 to gain 10% on the whole transaction.
Question
A shopkeeper purchased 60 article at rupees 158 he sold one third of them at a loss of 6% at what price must he sell the remaining so as to gain 10% on whole deal .
Answer
Given,
- total number of article = 60
- CP of each article = Rs.150
now CP of 60 articles
- 150 × 60 = Rs.9000
We know that ,
now putting the value we get ,
now total gain percent = 10%
we know that ,
now putting the values we get ;
now ,
gain = total sp - total cp
Then, we have ;
- Sp = SP of 20 articles + sp of 40
- cp = 9000
Now,
putting the value we get ;