Question

a shoreline is being washed away at the rate of 151/3 cm every year. a house is 151 / 5 m from the shore. if the erosion continues at the same rate, how far the water will the house be in 10 years

Answer 1

Rate = 151/3 cm/yr

Distance of the house from shore = 151/5 m = 151/5 × 100 cm = 3020 cm

So, distance of house from the shoreline after 10 years = 3020 - 151/3(10)
= 3020 - 1510/3
= 9060/3 - 1510/3
= 7550/3 cm
= 75/30 m
= 5/2 m

Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

A shoreline is being washed away at the rate of 151/3 cm every year. a house is 151 / 5 m from the shore. if the erosion continues at the same rate, how far the water will the house be in 10 years

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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Rate 151/3 cm/yr

Distance of the house from shore = 151/5

m 151/5 x 100 cm = 3020 cm

So, distance of house from the shoreline

after 10 years = 3020-151/3(10)

= 3020 - 1510/3

= 9060/3 - 1510/3

7550/3 cm

75/30m

=$\red{ 5/2 \:metre=2.5m}$

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