Question

a short bar magnet allowed to fall along the axis of horizontal metallic ring starting from rest the distance fallen by the magnet in one second maybe​

Answer 1

Answer:

s=ut+1/2gt^2

here, u=0 & t=1 sec

therefore, S=1/2*10*1

=5m (ans.)

Answer 2

Given that,

Time = 1 sec

Initial velocity = 0

We need to calculate the distance fallen by the magnet

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Where, u = initial velocity

g = acceleration due to gravity

t = time

Put the value into the formula

$s=0+\dfrac{1}{2}\times9.8\times1^2$

$s=4.9\ m$

Hence, The distance falls by the magnet in one second is 4.9 m.