Question

A short bar magnet of magnetic moment 10 A m2
is placed along x-axis at origin. The magnetic field
at (5 m, 0) is
[NCERT ​

Answer 1

Answer:

The torque acting on bar magnet is given as,

τ=M×B

τ=(10

i

^

)×(2

i

^

+3

j

^

)

τ=30

k

^

N⋅m

Thus, the torque acting on bar magnet is 30

k

^

N⋅m.