A short bar magnet of magnetic moment 10 A m2
is placed along x-axis at origin. The magnetic field
at (5 m, 0) is
[NCERT Pg. 177]
(1) 0.8 * 10-T
(2) 1.6 × 10-8 T
(3) 10-T
(4) Zero
Answers
Answer:
1.6×10^-8T
Explanation:
use the formula for magnetic field at axial position...
The magnetic field at (5 m, 0) is 1.6 x 10^-8 T.
Option(b) is the correct answer.
Given:
The magnetic moment of a bar magnet, M = 10 Am² are placed along the x-axis at the origin.
To Find:
The magnetic field at (5 m, 0).
Solution:
We are required to find the magnetic field at (5 m, 0).
The magnetic field formula for a short magnet is given as
B = (µ₀/4π ) x 2M/r³ -------(1)
Magnetic permeability, µ₀ = 4π x 10-7 N/A²
Magnetic moment, M = 10 Am²
r = 5 m
Substitute the value of µ₀, M, and r in the equation(1) we get
B = (10⁻⁷x2x10)/5³
B = (20x10⁻⁷) / 125
B = 0.16 x 10^-7
B = 1.6 x 10^-8 T
Therefore, The magnetic field at (5 m, 0) is 1.6 x 10^-8 T.
Hence, Option(b) is the correct answer.
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