A short dipole has dipole moment 10 -2 C m along negative Z axis. It is kept in an electric field along positive Z axis which uniformly increases at the rate of 10^3 N/C per metre. Find the net force and torque acting on the dipole.
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A dipole of dipole moment p is placed in a non uniform electric field along x axis. electric field is increasing at the rate of 1v/m then the force on dipole is...
Answer : force on dipole = p
explanation : given, A dipole of dipole moment p is placed in a non-unifrom
electric field along x - axis. Let us consider that E(x) is electric field along x-axis.
now, electric field is increasing at the rate of 1 V/m . i.e., dE(x)/dx = 1V/m.
we know, force due to dipole is given by, F = dipole moment × electric field gradient
= p × dE(x)/dx
= p × 1
= p
Hence, force on the dipole should be p ✔
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