A short electric dipole has a dipole moment of
16x 10-9 Cm. The electric potential due to the
dipole at a point at a distance of 0.6 m from the
centre of the dipole, situated on a line making an
angle of 60° with the dipole axis is:
1 N
=9x 109 Nm²/C2
4TTEO
Answers
Answer :
Dipole moment = 16 × 10 Cm
We have to find electric potential due to the dipole at a distance of 0.6m from the centre of the dipole situated on a line making an angle 60°
_________________________________
◈ Electric potential at distance r from centre of dipole making an angle Φ with dipole moment is given by
Answer:
Dipole moment = 16 × 10^{-9}
−9
Cm
We have to find electric potential due to the dipole at a distance of 0.6m from the centre of the dipole situated on a line making an angle 60°..
_________________________________
◈ Electric potential at distance r from centre of dipole making an angle Φ with dipole moment is given by
\dag\:\boxed{\bf{V=\dfrac{KP\cos\phi}{r^2}}}†
V=
r
2
KPcosϕ
\leadsto\sf\:V=\dfrac{(9\times 10^9)(16\times 10^{-9})\cos60\degree}{(0.6)^2}⇝V=
(0.6)
2
(9×10
9
)(16×10
−9
)cos60°
\leadsto\sf\:V=\dfrac{144\times 0.5}{0.36}⇝V=
0.36
144×0.5
\leadsto\sf\:V=\dfrac{72}{0.36}⇝V=
0.36
72
\leadsto\:\boxed{\bf{V=200\:volt}}⇝
V=200volt