A short sighted person cannot see clearly beyond 40cms calculate the power of lens to correct vision of the person ml
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2.5d lens is the kind of lens for him/ p=1/0.4m(f=40cm)=2.5D the person thus uses a convex lens......suffering from hypermetropia(a person can see the far away objects clearly but cannot see the near objects clearly.)
HemantNetha:
I want the process
Answered by
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Data:-u=-40cm
v=infinity
By lens formula
1/f=1/v-1/u
1/f=(1/infinity)-1/(-40)
1/f=0+1/40
f=40cm
=0.4m
By using power formula i.e.,
P=1/f
P=1/0.4
P=10/4
P=2.5D
Therefore,the power of the lens is 2.5D.
The person uses convex lens and is suffering from hypermetropia.
v=infinity
By lens formula
1/f=1/v-1/u
1/f=(1/infinity)-1/(-40)
1/f=0+1/40
f=40cm
=0.4m
By using power formula i.e.,
P=1/f
P=1/0.4
P=10/4
P=2.5D
Therefore,the power of the lens is 2.5D.
The person uses convex lens and is suffering from hypermetropia.
sir take f=40
not i
Yaa f is 40cm by converting it to m it becomes 0.4m
The unit of power is dioptre if and only if the focal length is in metres
correct
not change the f
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okkkk
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