Physics, asked by su98835, 1 month ago

A shot is fired horizontally with a velocity of 900 m/s from the top of a tower 100 m high. Find the distance from the foot of the tower where it strikes the ground. (g=9.8 m/s)​

Answers

Answered by guptaashesh4
0

Answer:

Explanation:

Given :    u  

x

=98m/s               a  

y

=g=9.8m/s  

2

 

Height of the hill          S  

y

=h=490  m

∴  Time of flight      T=  

g

2h

 

=  

9.8

2(490)

 

=10  s

Distance   BA (or horizontal range)        BA=u  

x

T=98×10=980m  

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