A shot is fired horizontally with a velocity of 900 m/s from the top of a tower 100 m high. Find the distance from the foot of the tower where it strikes the ground. (g=9.8 m/s)
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Answer:
Explanation:
Given : u
x
=98m/s a
y
=g=9.8m/s
2
Height of the hill S
y
=h=490 m
∴ Time of flight T=
g
2h
=
9.8
2(490)
=10 s
Distance BA (or horizontal range) BA=u
x
T=98×10=980m
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