Question

A shot is fired with a velocity of 100m/s in a direction making an angle 60⁰ with the vertical. Calculate the time of the flight, the maximum height reached and its horizontal range. (Use g=10ms‐²

Answer 1

Explanation:

time of flight =2u×sintheta /g

t=2×100×sin60/10

t=17.32sec

Hmax=u^2sin^2theta/2g

Hmax=(100)^2sin^260°/20

Hmax=375metres

Range=ucos60°×t

Range =50×17.32=866meters