Question

a shot is fired with a velocity of 200 ms-1 in a direction making an angle 30° with the vertical. calculate the time of flight and the maximum height reaches .​

Answer 1

Answer:

Time of Flight = 20.408 sec

Maximum height = 510.204m

Explanation:

Given,

u = 200m/s

θ = 30°

g = 9.8m/s²

Time of Flight (t) = 2usinθ/g

                           = [2 * 200 * sin30]/9.8

                           = 20.408 sec

Maximum Height (h) = u²sin²θ/2g

                                 = [(200)² * sin²30] / 2 * 9.8

                                 = 510.204m

I do so hope that this answer helps you mate!

Answer 2

Explanation:

Answer is 35.35 and 1,5305.5m