Question

a shot of mass 0.5kg travelling at 500m/s is stopped by sand at distance of 0.5m.find kinetic energy of the shot, average retardation and average resistive force due to sand

Answer 1

Mass = 0.5kg

u = 500m/s

v = 0m/s

s = 0.5m

Kinetic energy = ½mv²

= ½× 0.5×500²

=>½×0.5×250000

=>0.5×125000

=>62500 Joule

Kinetic energy of shot = 62500J or 6.25× 10⁴ J

By using equation,

v² = u²+2as

0 = 500² + 2×a×0.5

0 = 250000 + a

-250000 = a

Average retardation is 250000m/s²

Average acceleration is -250000m/s²

Average resistive force = mass×acceleration

=>0.5×(-250000)

=>-125000N

Average resistive force = 125000N or 1.25×10^5 N

Average force exerted = -125000N

Cheers!

Answer 2

Explanation:

that's the solution

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