Question

A shot-put is a metallic sphere of radius 2.1 cm. If the density of the metal is

8.9 g/cm3

. Find the mass of the shot-put.​

Answer 1

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Answer 2

Step-by-step explanation:

Given:-

A shot-put is a metallic sphere of radius 2.1 cm. If the density of the metal is 8.9 g/cm3

To find:-

Find the mass of the shot-put.

Solution:-

Radius of the metallic sphere (r)=2.1 cm

Volume of the sphere =(V)=(4/3)πr³ cubic units

Volume of the metallic sphere=

=>V=(4/3)×(22/7)×(2.1)^3

=>V=(4×22×2.1×2.1×2.1)/(3×7)

=>V=4×22×2.1×2.1×2.1/21

=>V=4×22×2.1×2.1×0.1

=>V=38.808 cm^3

Volume of the given metallic sphere=38.808 cm^3

Density of the metal =8.9g/cm^3

We know that

Density =Mass /Volume

Mass of the metal =Volume×Density

=>Mass of the metal=38.808×8.9 g

Mass of the metal=345.3912 g

Answer:-

Mass of the given metallic shot put =345.3912 g

Used formulae:-

• Volume of a sphere =(4/3)πr^3 cubic units

Where, r=radius of the sphere

and π=22/7

• Density =Mass /Volume
• Mass =Density ×Volume