Math, asked by nikunjch321, 2 months ago

a shot-put is a metallic sphere of radius 2.1cm. if the density of the metal is 8.9 g/cm3. Find the mass of the shot​

Answers

Answered by nikunjc971
2

Step-by-step explanation:

Since the shot-put is a solid sphere made of metal and its mass is equal to the product of its volume and density, we need to find the volume of the sphere.

Now, volume of the sphere =

3

4

πr

3

=

3

4

×

7

22

×4.9×4.9×4.9cm

3

=493cm

3

(nearly)

Further, mass of 1 cm

3

of metal is 7.8g

Therefore, mass of the shot-put =7.8×493g

=3845.44g=3.85kg (nearly)

Answered by rajveer032020
0

Answer:

First take the volume of sphere = (4*22)*(2.1)³/(3*7)

= 38.79 cm³

mass of metal = density * volume

= 8.9 * 38.79

= 345.231

= 345g

Hope it will help you

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