Question

a shot put is a metallic sphere of radius 4.9cm.If the density of the metal is 7.8g per cm cube, find the mass of the shot put.

Answer 1

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Radius of the shot put = 4.9 cm

Volume of the shot put = (4/3)πr3 cm3

= (4/3) x 22/ 7 x 4.9 x 4.9 x 4.9 cm3

Density of the shot put = 7.8 gm / cm3

Mass of the shot put = 7.8 x (4/3) x 22/ 7 x 4.9 x 4.9 x 4.9 gm

= 3845.44 gm

= 3.845 kg

Answer 2

Answer :

The mass of the shot put is 3.845 kg.

Step-by-step explanation :

Given :

Radius of metallic sphere = 4.9 cm

And density of the metal = 7.8 gm / cm³

Volume of sphere = $\sf \frac{4} {3}$π r³

⇒ $\sf \frac{4}{3} \times \frac{22}{7} \times 4.9 \times 4.9 \times 4.9$

⇒ $\sf \frac{1479.016} {3}$ cm³

Mass of the shot put = volume × density

⇒ $\sf \frac{1479.016} {3} \times 7. 8 gm$

⇒ 1479.016 × 2.6 gm

⇒ 3845. 44 gm

Hence, Mass of the shot put sphere is 3.845 kg. (approx)