A shot put metallic sphere of radius 3.5 cm. Of the density of they metal is 7.8 g per cm cube , find the mass of the shot put
Answers
Answer:
1.4014 kg
Step-by-step explanation:
Given ---> Radius of sphere = 3.5 cm
Density of the metal = 7.8 g / cm³
To find---> Mass of shotput = ?
Solution---> ATQ,
Radius of sphere = 3.5 cm
Volume of sphere = 4/3 × π r³
= 4 / 3 × 22 / 7 × ( 3.5 )³
= 4 / 3 × 22 / 7 × 3.5 × 3.5 × 3.5
= (4 × 22 × 0.5 × 3.5 × 3.5) / 3
= 539 / 3 cm³
We know that,
Mass = Density × Volume
So,
Mass of shotput = Density of metal × Volume of
shotput
= 7.8 × ( 539 / 3 )
= 2.6 × 539
= 1401.4 gm
We know that 1000 gm = 1 kg , so to change gm in to kg we have to divide by 1000.
Mass of shotput = 1401.4 / 1000 kg
= 1.4014 kg
Answer:
Step-by-step explanation:
r=3.5cm
v=4/3*22/7*(3.5)(3.5)(3.5)
=359.333333
=360(approx)
d=m/v
7.8=m/360
m=7.8*360
m=2808g