Question

A shot putt is a metallic sphere of radius 2.1 cm.If the density of the metal is 7.8 g per cu.cm , then the mass of the shot putt is :​

Answer 1

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Since the shot-put is a solid sphere made of metal and its mass is equal to the product of its volume and density, we need to find the volume of the sphere.

$\sf{Volume = \frac{4}{3} \pi{r}^{3} }$

$\sf{ = \frac{4}{3} \times \frac{22}{7} \times 2.1 \times 2.1 \times 2.1 = 38.80c {m}^{3} }$

$\sf{Density = \frac{mass}{volume} }$

$\sf{7.8 = \frac{mass}{308.80} }$

$\sf = 7.8 \times 308.80 = mass$

=2408.64g=2.40kg

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