Question

A shot - putt is a metallic sphere of radius 4.9 cm. If the density of the metal is 7.8 g/cm³, find the mass of the shot - putt.

{ANSWER WITH FULL EXPLANATION}

Answer 1

radius of metallic sphere = 4.9 cm

volume of metallic sphere = 4/3πr³

=> volume = 4/3×22/7×4.9×4.9×4.9

=> volume = 493.005 cm³

we know that , density = mass/volume

=> 7.8 g/cm³ = mass / 493.005 cm³

=> 7.8 g/cm³×493.005 cm³ = mass

=> 3845.439 g = mass

=> 3.845 kg = mass

hope this helps

Answer 2

Given
Radius =4.9cm
Density =7.8g/cm³

To find =mass

As we know density =mass/volume

So first of all we will calculate volume of sphere

Volume of sphere

$= \frac{4}{3} \pi \: {r}^{3}$
$= \frac{4}{3} \times \frac{22}{7} \times {4.9}^{3}$

Volume of sphere =493.005cm³

Putting it in formula

Density = mass/volume

7.8=mass/493.005

Mass=7.8x493.005

=3845.44g

=3.85kg
This is ur ans hope it will help you in case of any doubt comment