A SHOT PUTT IS METALLIC SPHERE OF RADIUS 4.9CM. IF THE DENSITY OF THE METAL IS 7.8 GM PER CU CM, FIND THE MASS OF THE SHOT-PUTT.
Answers
Answered by
3
Radius of shot put = 4.9 cm
Volume = 4/3 pi r^3
= 4/3 × 22/7 × 4.9 × 4.9 × 4.9
= 4 × 22 × 0.7 × 4.9 × 4.9 / 3
= 88 × 0.7 × 4.9 × 4.9 / 3
= 1479.016 / 3
Now,
Mass of shot put = Volume × density
= 7.8 × 1479.016 / 3
= 2.6 × 1479.016
= 3845.4416 g
= 3.8454416 kg
= 3.85 kg ( approx)
Volume = 4/3 pi r^3
= 4/3 × 22/7 × 4.9 × 4.9 × 4.9
= 4 × 22 × 0.7 × 4.9 × 4.9 / 3
= 88 × 0.7 × 4.9 × 4.9 / 3
= 1479.016 / 3
Now,
Mass of shot put = Volume × density
= 7.8 × 1479.016 / 3
= 2.6 × 1479.016
= 3845.4416 g
= 3.8454416 kg
= 3.85 kg ( approx)
Answered by
1
Radius of shot put = 4.9 cm
Volume = 4/3 pi r^3
= 4/3 × 22/7 × 4.9 × 4.9 × 4.9
= 4 × 22 × 0.7 × 4.9 × 4.9 / 3
= 88 × 0.7 × 4.9 × 4.9 / 3
= 1479.016 / 3
Now,
Mass of shot put = Volume × density
= 7.8 × 1479.016 / 3
= 2.6 × 1479.016
= 3845.4416 g
= 3.8454416 kg
= 3.85 kg ( approx)
hope it helped ⚡
braínlíest please ❤️
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