Question

(a) Show the formation of NazO and Mgo by the transfer of electrons. 3marks​

Answer 1

Answer:

give a correct question

Answer 2

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Atomic number of sodium - 11

Electronic configuration of sodium -

1s^2 2s^2 2p^6 3s^1

It has one valence electron, it will lose one electron to get octet configuration

Atomic number of oxygen - 8

Electronic configuration of oxygen -

1s^2 2s^2 2p^4

It is two electrons short of octet configuration, thus it will gain two electrons.

During the bond formation between sodium and oxygen, two sodium atoms loses one electron each to oxygen atom,

2Na - 2e^- => 2Na+

O + 2e^- => O^-2

2Na^+ + O^-2 => Na2O

Atomic number of Magnesium - 12

Electronic configuration of Magnesium -

1s^2 2s^2 2p^6 3s^2

It has two valence electrons , it will lose two electrons to get octet configuration

Atomic number of oxygen -8

Electronic configuration of oxygen −

1s^2 2s^2 2p^4

It is two electrons short octet configuration, thus it will gain two electrons.

During the bond formation between Magnesium and Oxygen, one magnesium atom loses two electrons to oxygen atom.

Mg - 2e^- => Mg2^+-

O - 2e^- => O^-2