. A shunt generator delivers 50 kW at 250 V and runs at 400 rpm. The armature and field resistances are 0.02 Ω and 50 Ω respectively. Calculate the speed of the machine running as a shunt motor and taking 50 kW input at 250 V. Allow 1 V per brush for contact drop.
Answers
The speed of the machine running as a shunt motor and taking 50 kW input at 250 V is 382 rpm.
Given : A shunt generator delivers 50 kW at 250 V and runs at 400 rpm
Resistance of armature is 0.02 ohm
Resistance of field is 50 ohm
Voltage of 1 V per brush for contact drop
To Find : The speed of the machine running as a shunt motor and taking 50 kW input at 250 V.
Solution : The speed of the machine running as a shunt motor and taking 50 kW input at 250 V is 382 rpm.
It is given that a shunt generator delivers 50 kW at 250 V and runs at 400 rpm , the armature and field resistances are 0.02 Ω and 50 Ω respectively and Voltage of 1 V per brush for contact drop
We have to find the speed of the machine running as a shunt motor and taking 50 kW input at 250 V.
We know that Power = Voltage × Current
P = V × I
The load current (I1) of the generator is
I1=
Power (P) is 50 kW = 50000 W
Voltage is 250 V
So I1 =
= 200 A
So load current is 200 A
Now we know that
V = IR
So field current is
I2 =
Voltage (V) is 250 V
Resistance (R) is 50 ohm
I2 =
= 5 A
So field current is 5 A
Now armature current is sum of load current and field current
I1+I2
= 200+5
=205 A
Armature drop is R × I
= 0.02 × 205
= 4.1 V
Hence induced emf inducting brush drop is
250 +4.1+2
= 256.1 volt
When input to motor is 50 kW , the line current is 200 A and since field current is 5 A ,
the armature current is 200-5 = 195 A
Now armature drop will be I × R
195 × 0.02
= 3.9 V
The net back emf will be 250 - 3.9 - 2
= 244.1 V
Hence speed of a machine running as a shunt motor is × 400
= 382 rpm.
So speed of the machine running as a shunt motor and taking 50 kW input at 250 V is 382 rpm.
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