a shuttle clock has the shape of a frustum of a cone mounted on a hemisphere the external diameter are 5cm &2cm the height of entire shuttle is 7cm finffind its external surface area
Answers
Answered by
16
External Surface area = (curved surface area of frustum) + (curved surface area of hemisphere)
= 22/7(r1+r2)l +2.22/7.r1
= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²
= 22/7 (3.5 × 6.18 +2) cm²
= 22/7 (21.63+2) cm²
= 22/7 × 23.63 cm²
= 519.86/7 cm²
= 74.26 cm²
= 22/7(r1+r2)l +2.22/7.r1
= 22/7 [(1+2.5)6.18 + 2×(1)²] cm²
= 22/7 (3.5 × 6.18 +2) cm²
= 22/7 (21.63+2) cm²
= 22/7 × 23.63 cm²
= 519.86/7 cm²
= 74.26 cm²
Purva1111:
my pleasure
Similar questions