Question

A side of a square is decreased by 3m and the other side is increased by 5m. Perimeter of the rectangle so formed is 36m. Find the area of the park not occupied by roads.​

Answer 1

Answer:

Area of the square is  64 square meter

Area of the rectangle formed is 65 square meter

Step-by-step explanation:

Let side of the square be  x meter

Side of square is decreased by 5 meter. ie $l =x-3 m$

Other side increased by 5 m ie $b = x+5 m$

Perimeter of the park is 36 m

$36 = 2(l+b)\\36=2(x-3+x+5)\\2x+2 = \frac{36}{2} \\2x= 18-2\\x=\frac{16}{2} \\x= 8 m$

Side of the square was 8 m

Area of the square is  8 x8 = 64 square meter

Area of the rectangle formed is

(8-3) (8+5)= 5* 13 = 65 square meter

Question is not clear. U have both areas. please comment the question

Answer 2

Answer:

The Area of rectangular park is 105 m²  

Step-by-step explanation:

Given as :

The perimeter of rectangular park = 36 meters

Let The sides of square = x meters

A side of square is decrease by 3 m

So, New side = L = ( x - 3 ) meters

Again

Other side is increase by 5 m

So, other side = B =  (x + 5) meters

∵  perimeter of rectangular park = 36 meters

So, 2 ( Length + breadth ) = 36

Or, (x - 3 ) + ( x + 5 ) = $\dfrac{36}{2}$

Or, 2 x - 2 = 18

Or, 2 x = 18 +2

Or, 2 x = 20

∴  x = $\dfrac{20}{2}$

i.e x = 10

So, L = ( x - 3 ) = 10  - 3 = 7 meters

And B =  (x + 5) = 10 + 5 = 15 meters

Since , Area of rectangle = Length × breadth

So, Area of rectangular park = L × B

Or,  Area of rectangular park = 7 meters × 15 meters

∴  Area of rectangular park = 105 m²

Hence, Area of rectangular park is 105 m²  Answer